.6=4.9(t^2)

Solution for .6=4.9(t^2) equation:

.6=4.9(t^2)

We move all terms to the left:

.6-(4.9(t^2))=0

We add all the numbers together, and all the variables

-(4.9t^2)+0.6=0

We get rid of parentheses

-4.9t^2+0.6=0

a = -4.9; b = 0; c = +0.6;
Δ = b2-4ac
Δ = 02-4·(-4.9)·0.6
Δ = 11.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{11.76}}{2*-4.9}=\frac{0-\sqrt{11.76}}{-9.8}
=-\frac{\sqrt{}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{11.76}}{2*-4.9}=\frac{0+\sqrt{11.76}}{-9.8}
=\frac{\sqrt{}}{-9.8}
$